Jim bought some chocolates and gave half of it to Ken. Ken bought some sweets and gave half of it to Jim. Jim ate 12 sweets and Ken ate 18 chocolates. The ratio of Jim’s sweets to chocolates became 1:7 and the ratio of Ken’s sweets to chocolates became 1:4. How many sweets did Ken buy?

This question I take from Yahoo! News la ... The answer is 68 but how to solve? Basket ... They really killing our youth ... No wonder lots of students senget wan ... lol

use algebra. they never learn meh?

I dunnoe ... I think this problem P4 do already ... Got 1 teacher show me a similar problem to this ... I said use algebra lo ... Best part ... Cannot use Algebra ...

draw one of those cute model blocks. hahaa

sorry, forgot to congratulate nam ... lol ... Congratz bro

Thanks for your time and effort ... lol

wah lau... this was from the newpapers... article about PSLE maths... ceh

Originally Posted by Cloud

use algebra. they never learn meh?

ya if use algebra its quite easy to see..

at start, let total number of chocolates be 2x and total number of sweets be 2y.

since at start, they share their sweets and chocolate, both have x chocolates and y sweets.

Jim ate 12 sweets, so he has x chocolates and (y - 12) sweets. Ratio of chocolates to sweet is 7:1.

x = 7y - 84

Ken ate 18 chocolates, so he has (x - 18) chocolates and y sweets. Ratio of chocolates to sweet is 4:1.

x - 18 = 4y

Solve for 2 equations and sweets bought = 2y